Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 20:57Z

det| 6 5 ; 4 7 | = 22

∇²ω = 0

460K

Fe₂O₃ + 3CO → 2Fe + 3CO₂

438K

∇²φ = 0

8ψ² + 7ψ + 0 = 0

186K

d/dt [t^3] = 3t^2

411K

\frac{9}{2} \sum_{i=1}^{n} i^{2}

6n² + 7n + 6 = 0

448K

∫₀^∞ e^(-t²) dt = √π / 2

22K

F = ma

∇ × E = −∂B/∂t

459K

\frac{12}{6} \sum_{i=1}^{n} i^{2}

406K

ΔS ≥ 0

AgNO₃ + NaCl → AgCl↓ + NaNO₃

∇²γ = 0