Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:02Z

10y² + 2y + 6 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∫₀^∞ e^(-z²) dz = √π / 2

438K

∫₀^∞ e^(-t²) dt = √π / 2

d/dt [t^3] = 3t^2

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∑_{k=1}^{n} k = n(n+1)/2

411K

e^{i\pi} + 1 = 0

∫₀^∞ e^(-θ²) dθ = √π / 2

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∂α/∂ω = 3α

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

e^{i\pi} + 1 = 0

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det| 9 4 ; 1 10 | = 86

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12γ² + 9γ + 1 = 0

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\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

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9θ² + 7θ + 4 = 0

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∫₀^∞ e^(-t²) dt = √π / 2

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