Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-17 23:05Z

Fe₂O₃ + 3CO → 2Fe + 3CO₂

∂ψ/∂β = 3ψ

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∂γ/∂z = 6γ

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

6ω² + 4ω + 4 = 0

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Fe₂O₃ + 3CO → 2Fe + 3CO₂

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ω = 2πf

F = G m₁m₂ / r²

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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e^{i\pi} + 1 = 0

\lim_{γ\to 0} \frac{\sin γ}{γ} = 1

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F = G m₁m₂ / r²

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10t² + 8t + 0 = 0

det| 7 4 ; 4 8 | = 40

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Fe₂O₃ + 3CO → 2Fe + 3CO₂

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∇ × E = −∂B/∂t

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