Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 03:06Z

e^{i\pi} + 1 = 0

Fe₂O₃ + 3CO → 2Fe + 3CO₂

460K

∇²r = 0

438K

F = ma

E = mc²

186K

d/dt [t^3] = 3t^2

411K

12θ² + 8θ + 3 = 0

8ψ² + 7ψ + 0 = 0

448K

ω = 2πf

22K

ω = 2πf

∑_{k=1}^{n} k = n(n+1)/2

459K

∇ × E = −∂B/∂t

406K

N₂ + 3H₂ ⇌ 2NH₃

ΔS ≥ 0

181K

det| 3 6 ; 0 4 | = 12

80K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

∑_{k=1}^{n} k = n(n+1)/2

359K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

455K

9x² + 4x + 5 = 0