Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 00:38Z

\binom{n}{k} = \frac{n!}{k!(n-k)!}

10β² + 4β + 1 = 0

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Fe₂O₃ + 3CO → 2Fe + 3CO₂

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d/dx [x^7] = 7x^6

E = mc²

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∂γ/∂z = 6γ

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

8ψ² + 7ψ + 0 = 0

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∇²γ = 0

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CH₄ + 2O₂ → CO₂ + 2H₂O

N₂ + 3H₂ ⇌ 2NH₃

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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10γ² + 8γ + 7 = 0

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det| 8 9 ; 4 9 | = 36

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iħ ∂ψ/∂t = Ĥψ

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∫₀^∞ e^(-α²) dα = √π / 2

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