Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:05Z

10y² + 2y + 6 = 0

d/dt [t^3] = 3t^2

460K

E = mc²

438K

∫₀^∞ e^(-t²) dt = √π / 2

∇ × E = −∂B/∂t

186K

5z² + 8z + 3 = 0

411K

e^{i\pi} + 1 = 0

det| 3 7 ; 2 4 | = -2

448K

∑_{k=1}^{n} k = n(n+1)/2

22K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

∑_{k=1}^{n} k = n(n+1)/2

459K

PV = nRT

406K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

181K

8ψ² + 7ψ + 0 = 0

80K

det| 2 8 ; 7 3 | = -50

359K