Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 01:39Z

CH₄ + 2O₂ → CO₂ + 2H₂O

Fe₂O₃ + 3CO → 2Fe + 3CO₂

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

264K

6α² + 6α + 5 = 0

d/dt [t^3] = 3t^2

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3z² + 5z + 1 = 0

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PV = nRT

6ω² + 4ω + 4 = 0

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Fe₂O₃ + 3CO → 2Fe + 3CO₂

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PV = nRT

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∇ × E = −∂B/∂t

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det| 2 3 ; 5 3 | = -9

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∫₀^∞ e^(-t²) dt = √π / 2

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8ψ² + 7ψ + 0 = 0

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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