Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 06:40Z

∑_{k=1}^{n} k = n(n+1)/2

∑_{k=1}^{n} k = n(n+1)/2

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5z² + 8z + 3 = 0

263K

e^{i\pi} + 1 = 0

d/dt [t^3] = 3t^2

139K

CH₄ + 2O₂ → CO₂ + 2H₂O

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2H₂ + O₂ → 2H₂O

det| 9 4 ; 1 10 | = 86

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4γ² + 1γ + 7 = 0

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det| 4 8 ; 0 5 | = 20

\frac{8}{7} \sum_{i=1}^{n} i^{2}

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∑_{k=1}^{n} k = n(n+1)/2

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