Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 14:30Z

3γ² + 8γ + 4 = 0

F = ma

460K

∇ × E = −∂B/∂t

438K

PV = nRT

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

186K

5φ² + 1φ + 1 = 0

411K

det| 1 9 ; 5 2 | = -43

det| 7 4 ; 4 8 | = 40

448K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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ω = 2πf

\lim_{α\to 0} \frac{\sin α}{α} = 1

459K

F = G m₁m₂ / r²

406K

7r² + 8r + 5 = 0

181K

\frac{8}{7} \sum_{i=1}^{n} i^{2}

80K