Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 06:40Z

∑_{k=1}^{n} k = n(n+1)/2

11z² + 3z + 4 = 0

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λ = h/p

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e^{i\pi} + 1 = 0

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

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∑_{k=1}^{n} k = n(n+1)/2

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2H₂ + O₂ → 2H₂O

det| 9 4 ; 1 10 | = 86

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1n² + 7n + 3 = 0

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det| 4 8 ; 0 5 | = 20

PV = nRT

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d/dt [t^3] = 3t^2

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det| 4 7 ; 7 5 | = -29

∑_{k=1}^{n} k = n(n+1)/2

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