Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 00:29Z

d/dy [y^8] = 8y^7

∇²n = 0

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\frac{2}{2} \sum_{i=1}^{n} i^{2}

264K

\lim_{x\to 0} \frac{\sin x}{x} = 1

d/dt [t^3] = 3t^2

297K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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d/dn [n^3] = 3n^2

iħ ∂ψ/∂t = Ĥψ

48K

11t² + 9t + 7 = 0

411K

∇ × E = −∂B/∂t

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∇ × E = −∂B/∂t

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det| 2 8 ; 7 3 | = -50

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∫₀^∞ e^(-t²) dt = √π / 2

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8ψ² + 7ψ + 0 = 0

109K

∇²γ = 0

184K