Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 20:38Z

det| 6 5 ; 4 7 | = 22

∫₀^∞ e^(-θ²) dθ = √π / 2

460K

∇ × E = −∂B/∂t

438K

∇²φ = 0

\lim_{t\to 0} \frac{\sin t}{t} = 1

186K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

411K

\frac{9}{2} \sum_{i=1}^{n} i^{2}

d/dt [t^3] = 3t^2

448K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

22K

F = ma

11t² + 9t + 7 = 0

459K

8ψ² + 7ψ + 0 = 0

406K

9α² + 7α + 5 = 0

181K

F = G m₁m₂ / r²

80K