Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 18:15Z

e^{i\pi} + 1 = 0

∑_{k=1}^{n} k = n(n+1)/2

451K

N₂ + 3H₂ ⇌ 2NH₃

264K

λ = h/p

e^{i\pi} + 1 = 0

297K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

252K

det| 6 7 ; 7 7 | = -7

det| 7 4 ; 4 8 | = 40

48K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

411K

∇²ψ = 0

∇²z = 0

377K

∑_{k=1}^{n} k = n(n+1)/2

299K

6n² + 7n + 6 = 0

401K

N₂ + 3H₂ ⇌ 2NH₃

420K