Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:47Z

∇²n = 0

∇²γ = 0

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7r² + 8r + 5 = 0

263K

9r² + 4r + 1 = 0

∫₀^∞ e^(-ω²) dω = √π / 2

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∑_{k=1}^{n} k = n(n+1)/2

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

F = G m₁m₂ / r²

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det| 7 4 ; 4 8 | = 40

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11γ² + 3γ + 6 = 0

\binom{n}{k} = \frac{n!}{k!(n-k)!}

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∇²r = 0

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\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1

9ψ² + 7ψ + 3 = 0

297K

e^{i\pi} + 1 = 0

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∇ × E = −∂B/∂t

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