Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:35Z

11n² + 5n + 4 = 0

∫₀^∞ e^(-θ²) dθ = √π / 2

460K

∫₀^∞ e^(-x²) dx = √π / 2

438K

∫₀^∞ e^(-x²) dx = √π / 2

ΔS ≥ 0

186K

8ψ² + 7ψ + 0 = 0

411K

4φ² + 6φ + 2 = 0

iħ ∂ψ/∂t = Ĥψ

448K

PV = nRT

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

N₂ + 3H₂ ⇌ 2NH₃

459K

N₂ + 3H₂ ⇌ 2NH₃

406K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

181K

2n² + 4n + 0 = 0

80K

det| 4 8 ; 3 5 | = -4

359K