Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:56Z

11n² + 5n + 4 = 0

N₂ + 3H₂ ⇌ 2NH₃

460K

∑_{k=1}^{n} k = n(n+1)/2

438K

∫₀^∞ e^(-x²) dx = √π / 2

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

186K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

411K

4φ² + 6φ + 2 = 0

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

448K

∑_{k=1}^{n} k = n(n+1)/2

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

e^{i\pi} + 1 = 0

459K

det| 8 9 ; 4 9 | = 36

406K

∇²t = 0

181K

∫₀^∞ e^(-t²) dt = √π / 2

80K

det| 7 4 ; 4 8 | = 40

359K

5z² + 8z + 3 = 0

455K