Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-17 22:39Z

N₂ + 3H₂ ⇌ 2NH₃

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∇ × E = −∂B/∂t

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9ψ² + 4ψ + 2 = 0

iħ ∂ψ/∂t = Ĥψ

43K

\lim_{β\to 0} \frac{\sin β}{β} = 1

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d/dβ [β^6] = 6β^5

iħ ∂ψ/∂t = Ĥψ

424K

e^{i\pi} + 1 = 0

76K

det| 6 1 ; 4 7 | = 38

\lim_{t\to 0} \frac{\sin t}{t} = 1

41K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

298K

d/dt [t^3] = 3t^2

447K

∇²n = 0

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11φ² + 4φ + 0 = 0

112K

8ψ² + 7ψ + 0 = 0

412K