Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 16:36Z

10γ² + 4γ + 3 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

CaCO₃ → CaO + CO₂

438K

d/dβ [β^11] = 11β^10

8ψ² + 7ψ + 0 = 0

186K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

411K

3x² + 4x + 6 = 0

∑_{k=1}^{n} k = n(n+1)/2

448K

iħ ∂ψ/∂t = Ĥψ

22K

CaCO₃ → CaO + CO₂

iħ ∂ψ/∂t = Ĥψ

459K

∑_{k=1}^{n} k = n(n+1)/2

406K

Fe₂O₃ + 3CO → 2Fe + 3CO₂

N₂ + 3H₂ ⇌ 2NH₃

181K

∑_{k=1}^{n} k = n(n+1)/2

80K

∑_{k=1}^{n} k = n(n+1)/2

det| 3 1 ; 7 4 | = 5

359K

F = ma