Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:57Z

11n² + 5n + 4 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

438K

∫₀^∞ e^(-x²) dx = √π / 2

F = G m₁m₂ / r²

186K

iħ ∂ψ/∂t = Ĥψ

411K

4φ² + 6φ + 2 = 0

det| 9 4 ; 1 10 | = 86

448K

∑_{k=1}^{n} k = n(n+1)/2

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

459K

∇²r = 0

406K

∇²ω = 0

d/dt [t^3] = 3t^2

181K

∂α/∂ω = 3α

80K

d/dr [r^2] = 2r^1

ΔS ≥ 0