Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 03:31Z

e^{i\pi} + 1 = 0

\frac{4}{6} \sum_{i=1}^{n} i^{2}

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

F = ma

6n² + 7n + 6 = 0

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det| 4 7 ; 2 5 | = 6

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12θ² + 8θ + 3 = 0

∑_{k=1}^{n} k = n(n+1)/2

448K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

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ω = 2πf

\lim_{γ\to 0} \frac{\sin γ}{γ} = 1

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PV = nRT

406K

N₂ + 3H₂ ⇌ 2NH₃

det| 7 4 ; 4 8 | = 40

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\frac{12}{6} \sum_{i=1}^{n} i^{2}

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N₂ + 3H₂ ⇌ 2NH₃

359K