Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 06:35Z

∑_{k=1}^{n} k = n(n+1)/2

d/dt [t^3] = 3t^2

273K

8x² + 2x + 7 = 0

263K

e^{i\pi} + 1 = 0

∇ × E = −∂B/∂t

139K

\lim_{β\to 0} \frac{\sin β}{β} = 1

108K

2H₂ + O₂ → 2H₂O

d/dx [x^3] = 3x^2

333K

det| 3 1 ; 7 4 | = 5

160K

det| 4 8 ; 0 5 | = 20

\frac{4}{6} \sum_{i=1}^{n} i^{2}

439K

PV = nRT

413K

2H₂ + O₂ → 2H₂O

297K

8ψ² + 7ψ + 0 = 0

128K

∑_{k=1}^{n} k = n(n+1)/2

404K