Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:47Z

∇²n = 0

∑_{k=1}^{n} k = n(n+1)/2

273K

9ψ² + 7ψ + 3 = 0

263K

9r² + 4r + 1 = 0

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

139K

d/dt [t^3] = 3t^2

108K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

PV = nRT

333K

det| 9 4 ; 1 10 | = 86

160K

11γ² + 3γ + 6 = 0

4γ² + 1γ + 7 = 0

439K

8x² + 2x + 7 = 0

413K

∑_{k=1}^{n} k = n(n+1)/2

297K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

128K