Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-17 22:37Z

N₂ + 3H₂ ⇌ 2NH₃

e^{i\pi} + 1 = 0

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10ψ² + 5ψ + 0 = 0

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9ψ² + 4ψ + 2 = 0

2n² + 4n + 0 = 0

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iħ ∂ψ/∂t = Ĥψ

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d/dβ [β^6] = 6β^5

8ψ² + 7ψ + 0 = 0

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\frac{4}{9} \sum_{i=1}^{n} i^{2}

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det| 6 1 ; 4 7 | = 38

det| 4 8 ; 3 5 | = -4

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\frac{2}{2} \sum_{i=1}^{n} i^{2}

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∑_{k=1}^{n} k = n(n+1)/2

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N₂ + 3H₂ ⇌ 2NH₃

297K