Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 13:37Z

F = ma

N₂ + 3H₂ ⇌ 2NH₃

273K

∑_{k=1}^{n} k = n(n+1)/2

263K

\lim_{β\to 0} \frac{\sin β}{β} = 1

\frac{8}{7} \sum_{i=1}^{n} i^{2}

139K

5φ² + 1φ + 1 = 0

108K

N₂ + 3H₂ ⇌ 2NH₃

det| 7 4 ; 4 8 | = 40

333K

∑_{k=1}^{n} k = n(n+1)/2

160K

e^{i\pi} + 1 = 0

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

439K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

413K

1r² + 8r + 1 = 0

∫₀^∞ e^(-x²) dx = √π / 2

297K

7t² + 1t + 0 = 0

e^{i\pi} + 1 = 0

7θ² + 7θ + 2 = 0

iħ ∂ψ/∂t = Ĥψ

∇ × E = −∂B/∂t