Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:46Z

11n² + 5n + 4 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

det| 4 7 ; 2 5 | = 6

438K

∫₀^∞ e^(-x²) dx = √π / 2

12γ² + 9γ + 1 = 0

186K

det| 12 1 ; 5 13 | = 151

411K

4φ² + 6φ + 2 = 0

F = ma

448K

ΔS ≥ 0

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

459K

d/dt [t^3] = 3t^2

406K

∇²ω = 0

7r² + 8r + 5 = 0

181K

∂γ/∂θ = 2γ

80K

d/dr [r^2] = 2r^1

e^{i\pi} + 1 = 0

359K

det| 9 4 ; 1 10 | = 86

455K