Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 16:16Z

∂ψ/∂φ = 6ψ

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

451K

8ψ² + 7ψ + 0 = 0

264K

11ψ² + 2ψ + 6 = 0

d/dt [t^3] = 3t^2

297K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

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λ = h/p

\binom{n}{k} = \frac{n!}{k!(n-k)!}

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∇ × E = −∂B/∂t

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\lim_{t\to 0} \frac{\sin t}{t} = 1

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9α² + 7α + 5 = 0

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