Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 14:51Z

3γ² + 8γ + 4 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

460K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

438K

PV = nRT

8ψ² + 7ψ + 0 = 0

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

411K

det| 1 9 ; 5 2 | = -43

∇ × E = −∂B/∂t

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e^{i\pi} + 1 = 0

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ω = 2πf

\lim_{α\to 0} \frac{\sin α}{α} = 1

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5z² + 8z + 3 = 0

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∂n/∂ψ = 6n

d/dt [t^3] = 3t^2

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∫₀^∞ e^(-ψ²) dψ = √π / 2

N₂ + 3H₂ ⇌ 2NH₃