Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 20:37Z

∑_{k=1}^{n} k = n(n+1)/2

∑_{k=1}^{n} k = n(n+1)/2

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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det| 8 9 ; 3 9 | = 45

det| 7 4 ; 4 8 | = 40

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det| 11 5 ; 0 12 | = 132

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

det| 11 4 ; 5 12 | = 112

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N₂ + 3H₂ ⇌ 2NH₃

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F = ma

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∑_{k=1}^{n} k = n(n+1)/2

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∑_{k=1}^{n} k = n(n+1)/2

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