Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:33Z

11n² + 5n + 4 = 0

det| 7 4 ; 4 8 | = 40

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det| 3 6 ; 0 4 | = 12

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∫₀^∞ e^(-x²) dx = √π / 2

det| 9 8 ; 3 10 | = 66

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∑_{k=1}^{n} k = n(n+1)/2

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4φ² + 6φ + 2 = 0

\binom{n}{k} = \frac{n!}{k!(n-k)!}

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∑_{k=1}^{n} k = n(n+1)/2

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∫₀^∞ e^(-φ²) dφ = √π / 2

N₂ + 3H₂ ⇌ 2NH₃

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∂α/∂ω = 3α

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N₂ + 3H₂ ⇌ 2NH₃

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

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