Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 16:50Z

10γ² + 4γ + 3 = 0

∇²n = 0

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∑_{k=1}^{n} k = n(n+1)/2

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d/dβ [β^11] = 11β^10

det| 7 4 ; 4 8 | = 40

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iħ ∂ψ/∂t = Ĥψ

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3x² + 4x + 6 = 0

N₂ + 3H₂ ⇌ 2NH₃

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∇²z = 0

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CH₄ + 2O₂ → CO₂ + 2H₂O

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N₂ + 3H₂ ⇌ 2NH₃

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∇²t = 0

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∫₀^∞ e^(-t²) dt = √π / 2

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∑_{k=1}^{n} k = n(n+1)/2

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\lim_{t\to 0} \frac{\sin t}{t} = 1

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