Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 02:49Z

det| 5 4 ; 6 6 | = 6

8ψ² + 7ψ + 0 = 0

460K

d/dt [t^3] = 3t^2

438K

∇²φ = 0

iħ ∂ψ/∂t = Ĥψ

186K

det| 5 6 ; 2 6 | = 18

411K

det| 12 5 ; 4 13 | = 136

ω = 2πf

448K

∇ × E = −∂B/∂t

22K

∑_{k=1}^{n} k = n(n+1)/2

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

459K

10ω² + 7ω + 4 = 0

406K

CaCO₃ → CaO + CO₂

∑_{k=1}^{n} k = n(n+1)/2

181K

det| 11 4 ; 5 12 | = 112

80K

ω = 2πf