Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:51Z

∇²n = 0

\binom{n}{k} = \frac{n!}{k!(n-k)!}

273K

8ψ² + 7ψ + 0 = 0

263K

9r² + 4r + 1 = 0

∇ × E = −∂B/∂t

139K

7γ² + 8γ + 3 = 0

108K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

d/dt [t^3] = 3t^2

333K

6t² + 6t + 4 = 0

160K

4t² + 3t + 3 = 0

439K

det| 3 6 ; 0 4 | = 12

413K

∂γ/∂θ = 2γ

297K

det| 3 7 ; 2 4 | = -2

128K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

404K