Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 11:37Z

∇²t = 0

det| 7 4 ; 4 8 | = 40

460K

∑_{k=1}^{n} k = n(n+1)/2

438K

det| 6 4 ; 3 7 | = 30

5z² + 8z + 3 = 0

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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ΔS ≥ 0

det| 9 8 ; 3 10 | = 66

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∇²r = 0

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1z² + 3z + 2 = 0

∂x/∂ψ = 6x

459K

det| 3 7 ; 2 4 | = -2

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7t² + 3t + 1 = 0

∇ × E = −∂B/∂t

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F = G m₁m₂ / r²

80K

∂α/∂ω = 3α

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