Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 02:17Z

Fe₂O₃ + 3CO → 2Fe + 3CO₂

8θ² + 8θ + 6 = 0

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∑_{k=1}^{n} k = n(n+1)/2

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\frac{8}{4} \sum_{i=1}^{n} i^{2}

N₂ + 3H₂ ⇌ 2NH₃

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∇²r = 0

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N₂ + 3H₂ ⇌ 2NH₃

det| 7 4 ; 4 8 | = 40

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∇²ω = 0

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4t² + 3t + 3 = 0

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det| 3 6 ; 0 4 | = 12

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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Fe₂O₃ + 3CO → 2Fe + 3CO₂

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∇²ω = 0

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