Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 20:37Z

det| 6 5 ; 4 7 | = 22

∑_{k=1}^{n} k = n(n+1)/2

460K

∇ × E = −∂B/∂t

438K

∇²φ = 0

6r² + 3r + 1 = 0

186K

CH₄ + 2O₂ → CO₂ + 2H₂O

411K

\frac{9}{2} \sum_{i=1}^{n} i^{2}

8ψ² + 7ψ + 0 = 0

448K

d/dt [t^3] = 3t^2

22K

F = ma

6t² + 6t + 4 = 0

459K

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

406K

ΔS ≥ 0

AgNO₃ + NaCl → AgCl↓ + NaNO₃