Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 01:31Z

11φ² + 9φ + 3 = 0

ΔS ≥ 0

460K

PV = nRT

438K

∫₀^∞ e^(-y²) dy = √π / 2

d/dt [t^3] = 3t^2

186K

3z² + 5z + 1 = 0

411K

\lim_{y\to 0} \frac{\sin y}{y} = 1

∑_{k=1}^{n} k = n(n+1)/2

448K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

22K

11φ² + 4φ + 0 = 0

459K

det| 9 4 ; 1 10 | = 86

406K

PV = nRT

181K

∫₀^∞ e^(-t²) dt = √π / 2

80K

∑_{k=1}^{n} k = n(n+1)/2

359K

F = G m₁m₂ / r²

455K