Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-17 22:38Z

N₂ + 3H₂ ⇌ 2NH₃

∇²β = 0

246K

5z² + 8z + 3 = 0

118K

9ψ² + 4ψ + 2 = 0

ΔS ≥ 0

43K

∑_{k=1}^{n} k = n(n+1)/2

261K

d/dβ [β^6] = 6β^5

det| 7 4 ; 4 8 | = 40

424K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

76K

det| 6 1 ; 4 7 | = 38

N₂ + 3H₂ ⇌ 2NH₃

41K

∫₀^∞ e^(-t²) dt = √π / 2

298K

λ = h/p

447K

ω = 2πf

297K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

112K