Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 20:28Z
det| 6 5 ; 4 7 | = 22
∑_{k=1}^{n} k = n(n+1)/2
460K
∑_{k=1}^{n} k = n(n+1)/2
438K
∇²φ = 0
\frac{9}{2} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
448K
F = ma
∑_{k=1}^{n} k = n(n+1)/2
459K
det| 9 4 ; 1 10 | = 86
406K
ΔS ≥ 0
det| 7 2 ; 7 8 | = 42
181K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
∑_{k=1}^{n} k = n(n+1)/2
359K
1φ² + 4φ + 5 = 0