Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:32Z

∇²n = 0

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

273K

det| 7 4 ; 4 8 | = 40

263K

9r² + 4r + 1 = 0

N₂ + 3H₂ ⇌ 2NH₃

139K

ω = 2πf

108K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

d/dx [x^9] = 9x^8

333K

6r² + 3r + 1 = 0

160K

11γ² + 3γ + 6 = 0

e^{i\pi} + 1 = 0

439K

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

413K

∇²r = 0

297K

∑_{k=1}^{n} k = n(n+1)/2

128K

e^{i\pi} + 1 = 0

404K

E = mc²

58K