Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-17 23:38Z

Fe₂O₃ + 3CO → 2Fe + 3CO₂

6ω² + 4ω + 4 = 0

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∑_{k=1}^{n} k = n(n+1)/2

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

Fe₂O₃ + 3CO → 2Fe + 3CO₂

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∫₀^∞ e^(-t²) dt = √π / 2

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ω = 2πf

N₂ + 3H₂ ⇌ 2NH₃

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det| 7 4 ; 4 8 | = 40

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e^{i\pi} + 1 = 0

\binom{n}{k} = \frac{n!}{k!(n-k)!}

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∇²t = 0

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10t² + 8t + 0 = 0

Fe₂O₃ + 3CO → 2Fe + 3CO₂

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