Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 20:52Z

det| 6 5 ; 4 7 | = 22

∇ × E = −∂B/∂t

460K

2H₂ + O₂ → 2H₂O

438K

∇²φ = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

186K

ΔS ≥ 0

411K

\frac{9}{2} \sum_{i=1}^{n} i^{2}

∇²r = 0

448K

E = mc²

22K

8ψ² + 7ψ + 0 = 0

459K

\lim_{β\to 0} \frac{\sin β}{β} = 1

406K

d/dt [t^3] = 3t^2

181K

e^{i\pi} + 1 = 0

80K

\frac{8}{7} \sum_{i=1}^{n} i^{2}

359K

2n² + 4n + 0 = 0

455K