Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 00:54Z

d/dy [y^8] = 8y^7

∫₀^∞ e^(-t²) dt = √π / 2

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∑_{k=1}^{n} k = n(n+1)/2

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\lim_{x\to 0} \frac{\sin x}{x} = 1

N₂ + 3H₂ ⇌ 2NH₃

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iħ ∂ψ/∂t = Ĥψ

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d/dn [n^3] = 3n^2

det| 7 4 ; 4 8 | = 40

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\lim_{t\to 0} \frac{\sin t}{t} = 1

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4t² + 3t + 3 = 0

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iħ ∂ψ/∂t = Ĥψ

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det| 9 5 ; 1 10 | = 85

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∇²z = 0

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iħ ∂ψ/∂t = Ĥψ

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