Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 02:49Z

det| 5 4 ; 6 6 | = 6

∑_{k=1}^{n} k = n(n+1)/2

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

∇²φ = 0

Fe₂O₃ + 3CO → 2Fe + 3CO₂

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d/dt [t^3] = 3t^2

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det| 12 5 ; 4 13 | = 136

CaCO₃ → CaO + CO₂

448K

∑_{k=1}^{n} k = n(n+1)/2

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∑_{k=1}^{n} k = n(n+1)/2

∇²γ = 0

459K

d/dφ [φ^1] = 1φ^0

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∇ × E = −∂B/∂t

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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8ψ² + 7ψ + 0 = 0

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