Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 14:48Z

3γ² + 8γ + 4 = 0

8ψ² + 7ψ + 0 = 0

460K

d/dt [t^3] = 3t^2

438K

PV = nRT

det| 1 4 ; 3 2 | = -10

186K

∑_{k=1}^{n} k = n(n+1)/2

411K

det| 1 9 ; 5 2 | = -43

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

448K

∇ × E = −∂B/∂t

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ω = 2πf

F = G m₁m₂ / r²

459K

8θ² + 8θ + 6 = 0

406K

∂n/∂ψ = 6n

∑_{k=1}^{n} k = n(n+1)/2

181K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

80K

N₂ + 3H₂ ⇌ 2NH₃