Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 15:32Z
11n² + 5n + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
438K
∫₀^∞ e^(-x²) dx = √π / 2
∑_{k=1}^{n} k = n(n+1)/2
411K
4φ² + 6φ + 2 = 0
∫₀^∞ e^(-φ²) dφ = √π / 2
∑_{k=1}^{n} k = n(n+1)/2
181K
det| 7 4 ; 4 8 | = 40
359K
det| 3 6 ; 0 4 | = 12
455K