Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-19 20:29Z
∑_{k=1}^{n} k = n(n+1)/2
∫₀^∞ e^(-ω²) dω = √π / 2
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det| 8 9 ; 3 9 | = 45
det| 4 7 ; 2 5 | = 6
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∑_{k=1}^{n} k = n(n+1)/2
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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
∑_{k=1}^{n} k = n(n+1)/2
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∑_{k=1}^{n} k = n(n+1)/2
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det| 7 4 ; 4 8 | = 40
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