Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 18:03Z

e^{i\pi} + 1 = 0

N₂ + 3H₂ ⇌ 2NH₃

451K

∫₀^∞ e^(-x²) dx = √π / 2

264K

λ = h/p

∇²r = 0

297K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

252K

det| 6 7 ; 7 7 | = -7

\frac{2}{2} \sum_{i=1}^{n} i^{2}

48K

8ψ² + 7ψ + 0 = 0

411K

∇²ψ = 0

iħ ∂ψ/∂t = Ĥψ

377K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

299K

∂γ/∂γ = 9γ

det| 4 2 ; 6 5 | = 8

401K

∑_{k=1}^{n} k = n(n+1)/2

420K

e^{i\pi} + 1 = 0

109K

det| 9 5 ; 1 10 | = 85

184K