Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 23:04Z

11t² + 8t + 0 = 0

8ψ² + 7ψ + 0 = 0

460K

∫₀^∞ e^(-t²) dt = √π / 2

438K

∂ω/∂β = 7ω

d/dt [t^3] = 3t^2

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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det| 3 3 ; 7 4 | = -9

∑_{k=1}^{n} k = n(n+1)/2

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∇ × E = −∂B/∂t

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\frac{2}{2} \sum_{i=1}^{n} i^{2}

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∑_{k=1}^{n} k = n(n+1)/2

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N₂ + 3H₂ ⇌ 2NH₃

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