Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 23:28Z

11t² + 8t + 0 = 0

det| 7 4 ; 4 8 | = 40

460K

11φ² + 4φ + 0 = 0

438K

∂ω/∂β = 7ω

∑_{k=1}^{n} k = n(n+1)/2

186K

N₂ + 3H₂ ⇌ 2NH₃

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det| 3 3 ; 7 4 | = -9

iħ ∂ψ/∂t = Ĥψ

448K

\frac{12}{6} \sum_{i=1}^{n} i^{2}

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∑_{k=1}^{n} k = n(n+1)/2

459K

CH₄ + 2O₂ → CO₂ + 2H₂O

406K

6t² + 6t + 4 = 0

181K