Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:59Z

11n² + 5n + 4 = 0

F = ma

460K

∑_{k=1}^{n} k = n(n+1)/2

438K

∫₀^∞ e^(-x²) dx = √π / 2

\binom{n}{k} = \frac{n!}{k!(n-k)!}

186K

CH₄ + 2O₂ → CO₂ + 2H₂O

411K

4φ² + 6φ + 2 = 0

det| 2 8 ; 7 3 | = -50

448K

det| 7 4 ; 4 8 | = 40

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

N₂ + 3H₂ ⇌ 2NH₃

459K

∂ψ/∂β = 3ψ

406K

det| 11 4 ; 5 12 | = 112

181K

∇²γ = 0

80K